CLA-11-03 Exam Dumps - CLA - C Certified Associate Programmer

This is the correct way to declare a pointer to an array of 10 int values. The parentheses are necessary to indicate that p is a pointer to an array, not an array of pointers. The base type of p is ‘an array of 10 int values’.12 References = 1: Pointer to an Array | Array Pointer - GeeksforGeeks 2: What is a pointer to array, int (*ptr) [10], and how does it work? - Stack Overflow

To understand the behavior of this program, let's first analyze its structure:

1.It includes the standard I/O library, , and the standard library, , although is not used in this program.

2.main function declares a double variable x initialized to 1234567890.0.

3.It then prints x using %f format specifier in printf.

Key Points to Consider:

•The double data type in C is typically capable of representing a wide range of deci-mal numbers quite accurately.

•The %f format specifier in printf is used for outputting a float or double as a fixed-point number.

•There may be some precision issues when dealing with floating-point numbers, but these generally occur with more complex calculations or when the numbers are ex-tremely large or small.

Given that 1234567890.0 is a straightforward decimal number well within the representable range of a double, and the program doesn't perform any complex calculations, we can ex-pect the output to be quite close to the actual value of x.

However, due to the way floating-point numbers are represented and handled in C, there can be slight discrepancies in the least significant digits due to rounding or representation errors.

This is because when you initialize u with some values, only one member of u will be as-signed a value at a time, and the rest will remain uninitialized. Therefore, when you print sizeof(u), it will show the size of the largest member, which is f in this case. Since f is 4 bytes long, sizeof(u) will be 4 bytes as well.

If you want to learn more about unions in C programming, you can check out these re-sources:

•C Unions - GeeksforGeeks

•C Unions (With Examples) - Programiz

•C - Unions - Online Tutorials Library

The program is not a valid C program and cannot be compiled successfully. The reason is that the program has two syntax errors:

•The function fun has a void return type, which means it cannot return any value. However, the function tries to return a floating-point value of 3.1415, which is incompatible with the re-turn type. This will cause a compilation error.

•The function main is defined inside the function fun, which is not allowed in C. A function cannot be nested inside another function. This will also cause a compilation error.

To fix these errors, the function fun should have a double return type, and the function main should be defined outside the function fun. For example:

#include

#include

double fun (void) { return 3.1415; }

int main (int argc, char *argv[]) { int i = fun(3.1415); printf(“%d”,i); return 0; }

References = C - Functions - Tutorialspoint, C - return Statement - Tutorialspoint, C Basic Syntax

The provided C program defines a struct S with one member i, a function fun that takes a struct S as an argument and decrements its i member, and a main function that creates a struct S, calls fun with it, and then prints the value of i from the struct.

Let's go through the main points of the program:

1.struct S str1 = { 2 }; initializes a struct S with i set to 2.

2.fun(str1); is called with str1 as an argument. However, since str1 is passed by val-ue, a copy of str1 is made for the function. The fun function then decrements i within its own copy of str1, and this decrement does not affect the original str1 in main.

3.k = str1.i; assigns the value of str1.i (which remains 2 because fun operated on a copy) to k.

4.printf("%d",k); prints the value of k, which is 2.

Given this, the correct answer is:

D. The program outputs 2.