Applied-Algebra Exam Dumps - WGU Applied Algebra FXO2 PFXP C957

The contractor charges a flat rate plus a fixed rate per hour, so this situation is modeled by a linear function:

C(t)=mt+b

where:

m= " hourly rate "

and

b= " flat rate "

We are given two points:

(3│220)

and

(5│340)

These mean:

A 3-hour job costs $220.

A 5-hour job costs $340.

First, find the hourly rate using slope:

m=(340-220)/(5-3)

m=120/2

m=60

So the contractor charges:

$60 " per hour "

Now the function has the form:

C(t)=60t+b

Use the point (3│220)to find the flat rate:

220=60(3)+b

220=180+b

b=40

So the function is:

C(t)=60t+40

Check with t=5:

C(5)=60(5)+40

C(5)=300+40

C(5)=340

This matches the given information.

Since xrepresents the number of years since 2003:

2003 ⇒ x=0

2007 ⇒ x=4

The average rate of change from 2003 to 2007 is:

(f(4)-f(0))/(4-0)

Find f(0):

f(0)=280× 〖 1.08 〗 ^0

f(0)=280

Find f(4):

f(4)=280× 〖 1.08 〗 ^4

f(4)≈380.94

Now calculate:

(380.94-280)/4

=100.94/4

≈25.23

Rounded to the nearest whole number:

25

Since the value is positive, the number of subscribers is increasing.

So the correct interpretation is:

" The number of subscribers increases at an average rate of 25 subscribers per year. "

Therefore, the correct answer is:

â–­ ( " C " )

The graph is a logistic growth curve.

A logistic growth curve has two main concavity regions:

" concave up before the inflection point "

and

" concave down after the inflection point "

From the graph, the function increases faster and faster until about:

x=6

After x=6, the graph continues increasing, but it begins to flatten out. That means the number of members is increasing slower and slower.

This is concave down behavior.

Therefore, one interval where the graph is concave down is:

(6│11)

So the correct answer is:

â–­ ( " D " )

The graph shows customer visits by day.

To determine which days likely featured new releases, we should look for the days with unusually high customer counts.

From the graph:

Day 8 has about 40customers.

Day 11 also has about 40customers.

These are the highest values shown on the graph.

Since the problem says more customers show up on days when new releases are featured, the days with the highest customer counts are the most likely new-release days.

Therefore, the correct answer is:

â–­ ( " D " )

The average rate of change measures how much the output changes per one unit of input.

Here:

t= " hours after 8:00 a.m. "

and

n(t)= " number of people at the park "

The two given points are:

A=(2,110)

and

B=(6,182)

This means:

At t=2hours after 8:00 a.m., there were 110people at the park.

At t=6hours after 8:00 a.m., there were 182people at the park.

Now calculate the average rate of change:

" Average rate of change " =(182-110)/(6-2)

=72/4

=18

Because the value is positive, the number of people is increasing.

So the correct interpretation is:

" The number of people at the park increases at an average rate of 18 people per hour. "