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What happens when you attempt to compile and run the following code?
#include
#include
#include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out<<val<<" "; } }; int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; vector v1(t, t+10); sort(v1.begin(), v1.end()); for_each(v1.begin(), v1.end(), Out(cout));cout<<endl; return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
set
s1.insert(v.begin(),v.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
for(set
cout<<*i<<" ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
int main() {
int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};
multimap
for (int i = 0; i < 10; i++) {
m.push_back(pair
}
for (multimap
cout << i?>first << " ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include <algorithm>
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int add (int a, int b) { return a+b; }
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
set
deque
d1.resize(s1.size());
transform(s1.begin(), s1.end(), v1.begin(), d1.begin(), add);
for_each(d1.begin(), d1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include <algorithm>
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int multiply (int a) {
return a*2;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
set
transform(s1.begin(), s1.end(), v1.begin(), multiply);
transform(v1.begin(), v1.end(), s1.begin(), multiply);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main()
{
cout.setf(ios::oct, ios::basefield);
cout<<100<<" ";
cout.setf(ios::showbase);
cout<<100<<" ";
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out<<val<<" "; } }; int main() { B t1[]={3,2,4,1,5}; B t2[]={6,10,8,7,9}; vector v1(10,0); sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); inplace_merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out(cout));cout<<endl; return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
bool mycomparison (int first, int second){return first>second;}
template
void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main()
{
int t1[] ={ 1, 7, 8, 4, 5 };
list
int t2[] ={ 3, 2, 6, 9, 0 };
list
l1.sort(mycomparison);
l2.sort(mycomparison);
l1.merge(l2,mycomparison);
print(l1.begin(), l1.end());
print(l2.begin(), l2.end()); cout<<endl;
return 0;
}